If a square + b square = 7ab then log a+b/3
Answers
Answered by
0
Answer:0
Step-by-step explanation:
log (a+b)/3
log (a+b)- log3
log(a+b)/3........(i) {log m/n= log m- log n}
a^2+ b^2= 7ab
(a+b)^2 - 2ab = 7ab
(a+b)^2= 9ab
a+b = 3√ab
Now put (a+b) value in equation (i)
log(3√ab)/3=0
By solving you'll get the answer
Answered by
1
Answer:
Hope it works................................™✌️✌️
Attachments:
Similar questions