Math, asked by rashmitha23, 11 months ago

if a square +b square + =81 ,and ab+bc+ca=18, find a+b+c​

Answers

Answered by vaibhavlspise2001
1

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

by putting given value we get

(a+b+c)²=81+2×18

=81+36

=117

a+b+c=√117=10.81

thank you

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