if a square +b square + =81 ,and ab+bc+ca=18, find a+b+c
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Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
by putting given value we get
(a+b+c)²=81+2×18
=81+36
=117
a+b+c=√117=10.81
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