if a square + b square + c square =16 and AB+BC+CA=10 find a+b+c
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Answered by
1
Hey mate!!
Here's your answer...
Given,
a^2 + b^2 + c^2 = 16
ab + bc + ca = 10
We know that,
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab +2bc +2ca
= a^2 + b^2 + c^2 + 2(ab + bc+ ca)
= 16 + 2(10)
= 16+20 = 36
a + b + c = √36
a + b + c =6
Therefore, a+b+c = 6
Hope it helped you...
Mark it as brainliest...
Answered by
2
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
Hope helps u
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