Question

If a square+b square+c square=16 and ab+bc+ca=10,find the value of a+b+c

Answer 1

Answer:

(a+b+c)^2-(2a+2b+2c)=a^2+b^2+c^2

(a+b+c)^2_2.10=16

a+b+c =6

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Answer 2

Answer:-

Given:

a² + b² + c² = 16 -- equation (1)

ab + bc + ca = 10 -- equation (2)

We know that,

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

→ (a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

Putting values from equation (1) & (2),

→ (a + b + c)² = 16 + 2(10)

→ (a + b + c)² = 36

→ (a + b + c) = √36

→ (a + b + c) = 6.