If a square+b square+c square=ab+bc+can, then a+c/b is equal to what?
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Step-by-step explanation:
a square+ b square+ c square=ab+bc+ac
multiply both sides by 2
2( a square+b square+c square)=2(ab+bc+ac)
2a square+2 b square+2 c square=2ab+2bc+2ac
a square+ a square+ b square+ b square+ c square+ c square-2ab-2bc-2ac=0
(a square+b square-2ab)+(b sqaure+ c square -2bc)+(c square+a sqaure-2ac)=0
this is of the form a- b the whole square
using a square-2ab +b square =(a-b) the whole square
(a-b) the whole square=0
implies a=b
similarly when we solve the other two we get a=b=c
substitute a+b/c=a+a/a
=2a/a=2
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