If a square + b square + c square equal = 16 and a b + BC + CA equal to 10 find the value of a + b + c
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5
(a+b+c)^2=20+16= a+b+c=6
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Answered by
17
given
a²+b²+c² = 16
ab +bc +ca = 10
since
(a+b+c)² = a²+b²+c²+2(ab+bc+ca)
= 16 +2(10)
= 16 +20 = 36
thus (a+b+c)² = 36
a+b+c = ±6
a²+b²+c² = 16
ab +bc +ca = 10
since
(a+b+c)² = a²+b²+c²+2(ab+bc+ca)
= 16 +2(10)
= 16 +20 = 36
thus (a+b+c)² = 36
a+b+c = ±6
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