Question

If a square + b square + c square equal to 50 and a b + BC + CA = 47 then find (a+b+c)

Answer 1

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Let's remember the identity

( a + b + c )² = ( a² + b² + c² + 2ab + 2bc + 2ca )

Now,

a² + b² + c² = 50
ab + bc + ca = 47

( a + b + c )² = [ a² + b² + c² + 2( ab + bc + ca ) ]

( a + b + c )² = 50 + 2( 47 )

( a + b + c )² = 50 + 94

( a + b + c ) = √144

a + b + c = 12

$\textbf{ Hence Answer is 12 }$

Hope it helps

Answer 2

Answer:

Step-by-step explanation: