if a square + b square + c square equals to 220 and a b + BC + ca = to 4 then find the value of a + b +c
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(a+b+c)²=a²+b²+c²+2(ab+bc+ca)
(a+b+c)²=220+2(4)
(a+b+c)²=228
a+b+c=√228
(a+b+c)²=220+2(4)
(a+b+c)²=228
a+b+c=√228
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