if a square + b square + c square equals to 250 and a b + BC + CA = 23 find the value of a + b + c
Answers
Answered by
2
Solution :
a² + b² + c² = 250 ----( 1 )
ab + bc + ca = 23 -----( 2 )
( a + b + c )² = a²+b²+c²+2ab+2bc+2ca
= a² + b² + c² + 2( ab + bc + ca )
= 250 + 2 × 23
= 250 + 46
= 296
=> a + b + c = √296
= √296
= √(2×2×2×37)
= 2√74
••••
a² + b² + c² = 250 ----( 1 )
ab + bc + ca = 23 -----( 2 )
( a + b + c )² = a²+b²+c²+2ab+2bc+2ca
= a² + b² + c² + 2( ab + bc + ca )
= 250 + 2 × 23
= 250 + 46
= 296
=> a + b + c = √296
= √296
= √(2×2×2×37)
= 2√74
••••
Similar questions