if a square + b square + c square equals to 250 and ab+bc+ca equals to 3 then find the value of a + b + c
Answers
Answered by
247
using formula (a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)
=250+2(3)
=256
(a+b+c)^2= 256
a+b+c= √256
= 16
=250+2(3)
=256
(a+b+c)^2= 256
a+b+c= √256
= 16
NeelamG:
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Answered by
139
a2+b2+c2=250
ab+bc+ca=3
therefore (a+b+c)2=a2+b2+c2+2(ab+bc+ca)
(a+b+c)2 = 250 + 6
(a+b+c)2 = 256
(a+b+c) =square root (256)
=16
ab+bc+ca=3
therefore (a+b+c)2=a2+b2+c2+2(ab+bc+ca)
(a+b+c)2 = 250 + 6
(a+b+c)2 = 256
(a+b+c) =square root (256)
=16
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