if a square + b square + c square is equal to 600 AB + BC + CA is equal to 212 find a + b + c
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Answered by
1
Answer:
(a+b+c)^2 = (a^2 + b^2 + c^2) +2ab + 2bc + 2ca
= (600)+ 2(ab+bc+ca)
= 600 + 2(212)
= 600+ 424
= 1024
since, (a+b+c)^2 = 1024
therefore, (a+b+c) = 32
:))
Answered by
1
Answer:
32
Step-by-step explanation:
(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)
(a+b+c)^2 = 600 + 2(212)
(a+b+c)^2 = 1024
(a+b+c) = √1024
(a+b+c) = 32
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