Question

If a square + b square +c swap is equal to 200 and ab + bc + ca is equal to 28 find the value of a + b+ c

Answer 1

Answer:

Step-by-step explanation:

16.

Answer 2

Answer:

16

(a+b+c)^ 2= a ^2+b ^ 2 + c^ 2+2ab+2 bc+ 2ca

(a+b+c)^2= a^2+ b^2+c ^2+2(ab+bc+ca)

Given a square+ b square+c square is 200

ab+bc+ca is 28

substituting

200+2(28)

200+56

256=(a+b+c)^ 2

transpose square it becomes root

a+b+c=√256

16

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