Question

If a square + b square is equal to 117 ab is equal to 54 find the value of (a + b)and (a-b) a square minus b square

Answer 1

Answer:

Step-by-step explanation:

a^2 + b^2 = 117

ab = 54

(a+b)^2 - 2ab = a^2 + b^2

(a+b)^2 - 2x54 = 117

(a+b)^2 = 117 + 108

(a+b)^2 = 225

(a+b) = 15

(a-b)^2 = (a+b)^2 - 4ab

(a-b)^2 = 225 - 216

(a-b)^2 = 9

(a-b) = 3

(a+b)(a-b) = 15 x 3

a^2 - b^2 = 45