Question

If a square + b square is equal to 13 and a b is equals to 6 find a + b and a minus b​

Answer 1

Answer:

Hey Mate!! Let me help you for this question......

Given:

=>  $a^{2} +b^{2} = 13$

=> ab = 6 and 2ab = 12

To Find:

(a + b)(a - b)

Solution:

Before starting the solution we need to know one thing.....

We know,

=>  $(a-b)^2=a^2+b^2-2ab$

=>   $a^2+b^2=(a-b)^2+2ab$ (Just transposed 2ab term the other side)

Now we have just substitiue the values in this equation.....

=>  $13=(a-b)^2+12$

=>   $(a-b)^2=1$

Therefore  (a - b) = 1

Also,

=>  $a^2+b^2=(a+b)^2-2ab$

=>  $13=(a+b)^2-12$

=>  $(a+b)^2 =25$

Therefore (a + b) = 5

So, (a + b)(a - b) = (5)(1) =5

Hope this answer helped you...

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