if a square + b square is equal to 9 and a b is equal to 4 find the value of 3 bracket a + b square - 2( a- b)^2
whole square
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Given :- a²+b²= 9 and ab= 4
Now we have to find the value of the equation 3(a+b)² - 2(a-b)²
3(a+b)² - 2(a-b)²
= 3(a²+b²+2ab) - 2(a²+b²-2ab)
Putting a²+b²=9 and ab=4
= 3(9+8) - 2(9-8)
= 3(17) - 2(1)
=51-2
=49
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