Question

if a square + b square ka whole cube equal to a cube plus b cube ka whole square and a b not equal to zero then the numerical value of a by b + B Y is equal to

Answer 1

$( {a}^{2} + {b}^{2} ) {}^{3} = ( {a}^{3} + {b}^{3} ) {}^{2} \\ {a}^{6} + {b}^{6} + 3( {a}^{4} {b}^{2} ) + 3( {a}^{2} {b}^{4} ) = {a}^{6} \\ + {b}^{6} + 2( {a}^{3} {b}^{3} ) \\ 3 {a}^{4} {b}^{2} + 3 {a}^{2} {b}^{4} = 2 {a}^{3} {b}^{3} \\ take \: {(ab)}^{2} common \\ 3 {a}^{2} + 3 {b}^{2} = 2ab \\ 3( \frac{a}{b} + \frac{b}{a} ) = 2 \\ \frac{a}{b} + \frac{b}{a} = \frac{2}{3}$
so here is your answer.... mark as brainliest if helped

Answer 2

Answer:

equation A) is the main equation to get the value of a/b+b/a,

(a^2+b^2)^3=(a^3+b^3)^2 --->A)

now you are required to open above equation using ,

(a+b)³ and (a+b)² formula,

so that

a^6+b^6+3a^4b^2+3b^4a^2=a^6+b^6+2(a^3b^3)

3a^4b^2+3b^4a^2=2(a^3b^3)

now take (ab)^2  as common

3(a/b+b/a)=2

a/b+b/a=2/3

so that correct value of a/b+b/a is 2/3