Question

If a square is formed by the diagonal of the square as an edge, what is the ratio between the area?

Answer 1

let the side of the square be x
so by Pythagoras theorem the diagonal=√2x


the required ratio be
$\frac{ {x}^{2} }{{( \sqrt{2}x) }^{2} } = \frac{ {x}^{2} }{2 {x}^{2} } = \frac{1}{2}$
1:2

Answer 2

Answer:

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