Question

If a square is insribed in a circle find the side of square if diameter of circle is 10 cm.
Plz solve this ..............​

Answer 1

Step-by-step explanation:

connect the OA , OB , OC , OD

OA =OB=OC=OD=10CM

AC=OA +OC=10+10=20

BD=OB+OD=10+10=20

Now areaof(ABCD)

=AC×BD×1/2

=10×10×1/2

=50

ONE SIDE OF (ABCD)= √50

=>5√2

Answer 2

Answer:

the diagonal of a square is given by √2a a is the side of square remember all four sides of square are equal.

here diameter of circle (take AOC) is equal to diagonal of square AC

that's why 10=√2a

a( side of square) = 10/√2

a= 5√2

hey if you want to know proof that diagonal AC = √2 (side of square) then take triangle AOCD and apply Pythagoras theorem remember AD=DC=say a