Question

if a square minus 3 + 1 equal to zero find a square + 1 by a square and a cube plus one the eq for confirmation of the answer is the answer of a square + 1 by a square equal to 7 and a cube + 1 by a cube equal to 18

Answer 1

a square +1 by a square is equal to $\dfrac{3}{2}$  and a cube plus one is equal to $2 \sqrt 2+1$.

• Given,
• a square minus 3 +1 equal to zero
• ⇒
• $a^2-3+1=0\\\\a^2-2=0\\\\a^2=2\\\\a=\sqrt 2$
• Now,
• a square +1 by a square
• $\dfrac{a^2+1}{a^2}\\\\=\dfrac{2+1}{2}\\\\=\dfrac{3}{2}$
• and,
• a cube plus one
• ∴$a^3+1$$a^3+1\\\\=(\sqrt 2)^3+1\\\\=2\sqrt 2 +1$

Answer 2

Answer:

The answer for given expression is 0.515    

Step-by-step explanation:

Given as :

( a² - 3 ) + 1 = 0

or, a² - 2 = 0

Or, a² = 2

∴     a = √2

(1)   $\dfrac{(a^{2}+1) }{a^{2}+a^{3}+1}$  

Or, $\dfrac{(2+1) }{2+(\sqrt{2}) ^{3}+1}$

Or, $\dfrac{3 }{3+(\sqrt{2}) ^{3}}$

Or, $\dfrac{3 }{3+2.82}$

Or, 0.515

Hence, The answer for given expression is 0.515     . Answer