Question

if a square minus b square is equals to 13 where A and B are natural numbers then the value of a is​

Answer 1

$a^2-b^2=13\\\\(a+b)(a-b)=13\times1\\\\\\a-b=1\implies a=b+1\\\\\\a+b=13\\\\(b+1)+b=13\\\\2b=12\\\\b=6\\\\\\a=6+1=7$