Question

If a square of area 44 sq.cm is divided into four congruent triangles, what is the
area of each triangle?​

Answer 1

• Note: Triangle DEF is similar to triangle ABC

Find the area of triangle ABC:

$\dfrac{\text {Area of }\triangle \text {1} }{\text {Area of }\triangle \text {2} } = \bigg( \dfrac{\text {Length of }\triangle \text {1} }{\text {Length of }\triangle \text {2}}\bigg)^2$

$\dfrac{\text {44} }{\text {Area of }\triangle \text {2}} = \bigg( \dfrac{2}{3} \bigg)^2$

$\dfrac{\text {44} }{\text {Area of }\triangle \text {2}} = \dfrac{4}{9}$

$4 \times \text {Area of }\triangle \text {2}$

$4 \times \text {Area of }\triangle \text {2}$

$\text {Area of }\triangle \text {2} = 396 \div 4$

$\text {Area of }\triangle \text {2} = 99 \text{ m}^2$

• Answer: The area is 99 m²

Answer 2

Given:

A square area =44 sq.cm

And that square is divided into four congruent triangles.

To find::

Area of each triangle

Since a square is divided into 4 congruent TRIANGLES

$\sf{area \: of \: each \: triangle = \frac{area \: of \: square}{4} }$

=>44/4= 11 sq.cm

$\sf{} \therefore{}area \: of \: each \: triangle = 11sq.cm$