Question

if a=square root 6+ square root 5/square root6-square root5 and b= square root 6- square root 5/square root6+square root5 then 1/a+1/b​

Answer 1

Step-by-step explanation:

a=

$( \sqrt{6} + \sqrt{5 } ) \div ( \sqrt{6 } - \sqrt{5} )$

b=

$(\sqrt{6} - \sqrt{5} ) \div (\sqrt{6} + \sqrt{5} )$

1/a = b and 1/b = a

1/a + 1/b = a + b

=

$( \sqrt{6} + \sqrt{5} ) ^{2} + ( \sqrt{6} - \sqrt{5} ) ^{2}$

=6+5+(2*√30)

=11+2√30