If a statement p(n) is true for n= k+1 , then can we conclude that it is true for n = k ?
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Answers
Answer:
Yes P(k + 1) is true, whenever P(k) is true.
Hence, by the Principle of Mathematical Induction, P(n) is true for all n ∈ N
Step-by-step explanation:
If the statement is true for n = k (where k is a particular but arbitrary natural
number), then the statement is also true for n = k + 1, i.e, truth of P(k) implies
the truth of P(k + 1). Then P(n) is true for all natural numbers n.
Example 1 1 + 3 + 5 + ... + (2n – 1) = n^2
Solution : Let the given statement P(n) be defined as P(n) : 1 + 3 + 5 +...+ (2n –1) = n^2
, for n ∈ N. Note that P(1) is true, since
P(1) : 1 = 1^2
Assume that P(k) is true for some k ∈ N, i.e.,
P(k) : 1 + 3 + 5 + ... + (2k – 1) = k^2
Now, to prove that P(k + 1) is true, we have
1 + 3 + 5 + ... + (2k – 1) + (2k + 1)
= k^ 2 + (2k + 1)
= k ^2 + 2k + 1 = (k + 1)^2
Thus, P(k + 1) is true, whenever P(k) is true.
Thus, P(k + 1) is true, whenever P(k) is true. Hence, by the Principle of Mathematical Induction, P(n) is true for all n ∈ N
Hope it works....
Answer :-
We are provided with a statement which says
p(n) is true for n = k +1
Now it is asking can we conclude that
p(n) is true for n = k
Well first we should go through the Principle of induction.
First Principle of Mathematical Induction
Let p(n) be a statement involving Natural number n such that.
i⟩ p(1) is true and
ii⟩ p(m) is true and
iii⟩ p(m + 1) is true
Then the statement p(n) is true for all the n Natural numbers.
Second Principle of Mathematical Induction
Let p(n) be a statement involving Natural number n such that.
i⟩ p(1) is true and
ii⟩ p(m + 1) is true whenever p(n) is true for all n where 1 ≤ n ≤ m
Then the statement p(n) is true for all values of n ( Natural numbers)
Now we are able to see
p(m + 1) is only true when p(m) is true and p(1) is true .
So we can say that
p(k + 1) is only true when p(k) is true
also p(1) should be true.
So when p(k + 1) is true then we can say that p(k) is true.
Now we generalise it as when
p(k) and p(k + 1) is true then p(n) is true when n belongs to Natural numbers.
Note that :- There are some sequence where the situation is defined ,, there the p(1) is the can be written as p(a) where a is the first term according to the given situation.