Question

If a stone is thrown upwards with velocity 50 m/s from the height of 90 m find its velocity at the height 40

m from the ground?​

Answer 1

Explanation:

Initial Velocity u=40

Initial Velocity u=40Fianl velocity v=0

Initial Velocity u=40Fianl velocity v=0Height, s=?

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motion

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×s

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss=

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20160

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20160

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20160

Initial Velocity u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20160 ⇒s=80m/s