If a stone is thrown upwards with velocity 50 m/s from the height of 90 m find its velocity at the height 40 m from the ground?
Answers
Answered by
1
Step-by-step explanation:
Initial Velocity u=50
Final velocity v=0
Height, s=?
By third equation of motion
v^2-u^2 = 2gs
0-50^2= 2 x 10 x s
s= 125m/s
Total distance travelled by stone = upward distance + downwars distance =2 x s = 250
Total Diaplacement =0, Since the initial and final point is same.
mark me as brainliest
Similar questions