Question

if a stone is thrown vertically up and it is caught after time t seconds, then the maximum height reached by it is ..............?​

Answer 1

Dear student,

Let the initial velocity is u, maximum height is h.

Velocity at maximum height = 0

Time taken in upward motion = Time taken in downward motion = t0/2.

For upward motion,

v=u-gt⇒u=gt02

h=ut-12gt2⇒h=gt02t02-12gt024⇒h=gt028

Regards

Answer 2

Answer:

let initial velocity be u

on reaching maximum height the final velocity v becomes zero