If a stone is thrown vertically upward with a velocity 10ms¹.what is the maximum height reached by the stone?
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Answer:
ans is 5m
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Answer:
Initial velocity (u)= 10 m/s
Final velocity (v) = 0 m/s
Acceleration due to gravity (g)= 9.8 m/s²
Height (j)= ?
Using the third equation of motion,
v²= u²-2gh
=> (0)² = (10)² -2*9.8*h
=> 0 = 100 - 19.6h
=> -100/19.6 = -h
=> 5.1= h
Therefore height = 5 m
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