Question

If a stone of mass 0.25 kg tied to a string executes uniform circular motion with a speed of 2 ms-1

of

radius 3m. What is the magnitude of tensional force acting on the stone?​

Answer 1

Answer:

f. = mv2/r

cp

f. = 1/4 x (2)square / 3 = 0.333 N

cp

Answer 2

Given:

A stone of mass 0.25 kg tied to a string executes uniform circular motion with a speed of 2 ms-1

of radius 3m.

To find:

Magnitude of tension in the string ?

Calculation:

• When the stone is executing the circular trajectory, the tension in the string will be equal to the CENTRIPETAL FORCE

$T = f_{c}$

$\implies T = \dfrac{m {v}^{2} }{r}$

$\implies T = \dfrac{0.25 \times {2}^{2} }{3}$

$\implies T = \dfrac{0.25 \times 4}{3}$

$\implies T = \dfrac{1}{3}$

$\implies T \approx \: 0.33 \: N$

So, tension in wire is 0.33 N