If a student cycles to school at the speed of 4 km/hr, then he gets late by 15 minutes. If he
cycles at the speed of 6 km/hr, then he is 5 minutes early. What is the distance to school ?
What should be his speed if he wants to reach the school just in time ?
Answers
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Step-by-step explanation:
Let the distance be x km.
Time= Distance
Speed
T1= x
4
T2 = x
6
Let the time he needs to arrive is t n the first case
T= T1 - 15
60
In second case,
T= T2 + 5
60
=> x/6 + 5/60 = x/4 - 15/60
=> 20/60 = x/4 - x/6
=> 1/3 = x/12
=> x=4 km
Hope you find this helpful!!!
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