if a student walks at 5 km per hour he reaches schoool 5 minuts early and if he walks at 4 km per hour he reaches school 5 minutes late .what is actual distance between student's house and school
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Let the distance be x km and
ATQ we have x/5 + 5/60=x/4-5/60
then we have x/4-x/5= 5/60+5/60
5x-4x=20*10/60
x= 20/6 km=3.33
Distance is 3.3 km
ATQ we have x/5 + 5/60=x/4-5/60
then we have x/4-x/5= 5/60+5/60
5x-4x=20*10/60
x= 20/6 km=3.33
Distance is 3.3 km
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