if a sum of two numbers is 1600 if 12% of a number is equal to 20%of the other . find numbers
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Step-by-step explanation:
Answer:
let 1st no is x so 2nd will be 1600-x
a.t.q.
12% of 1st=20% of 2nd
0.12x= 0.20(1600-x)
0.12x= 320-0.20x
0.32x= 320
x= 320 / 0.32
x= (320 * 100) / 32
x=1000 --Ans
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Let the first number be x and the second number be y.
Given : The sum of two numbers is 1600.
i.e. (1)
12% of one number = 0.012x
20% of the other number = 0.20y
If 12% of one is equal to 20% of the other
Put y=0.6x in (1) , we get
From (1) , y= 600
Hence, the numbers are 1000 and 600.Answer:
The numbers are 1000 and 600.
Explanation:
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