Question

if a surface encloses +1.6 *10^-19C, - 4.8 *10^-19C and +3.2*10^-19C charge within it, what is the electric FLUX linked to it.

Please give all the steps taken. ​

Answer 1

We know that electric flux is given by q/ε°

So the flux associated with 1.6 x 10^-19 will be

1.6 x 10^-19/8.85 x 10^-12 = 0.18 x 10^-7 or 1.8 x 10^-8

Incase of 4.8 x 10^-19

Φ = 5.4 x 10^-8

For 3.2 x 10^-19

Φ = 3.6 x 10^-8

I hope this helps you.

Incase you still have doubt feel free to ask.

Answer 2

Answer:actually bro its simple the elctric flux linked is 0

Explanation:electric flux =charge inclosed /permitivity of free space(epsilon)

Now since net charge inclosed is 0

Eletric flux is 0

Hope this helps

Even attached a file to let you see how i came yo that solution