Question

If a system of equation - ax+y+z=0
x - by+z=0
x+y- cz=0 (a, b, c #-1)
1
1 1 1
has a non-zero solution then { 1/(1+ a)}+{1/( 1+b)} +{1/ (1+C)}=
(a) 0
(b) 1
(c) 2
(d) 3​

Answer 1

Step-by-step explanation:

has a non-zero solution then { 1/(1+ a)}+{1/( 1+b)} +{1/ (1+C)}=b) 1