Question

If a = tan6 tan 42
and B = cot66 cot 78
then
(a) A = 2B (b)
1
AB
3
=
(c) A = B (d) 3A = 2B.

Answer 1

Answer:

We have

A= tan 6°tan 42°

And

B= cot 66°cot78°

So

A/B = ?

A/B = tan 6°tan42°tan 66°tan78°

Using

Tan(60-x)tan x tan (60+x)=tan3x

For x= 18°

So

tan42°tan18°tan78°=tan54°....... (1)

For x=6°

We get,

tan 54°tan6°tan66°=tan18°........... (2)

Eliminating tan 54° between (1) and (2)

We get

tan6°tan42°tan66°tan78°=1

So

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/ A/B= 1 /

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That's your answer,

Mark as brainlist

Answer 2

Step-by-step explanation:

a=tan6 tan42

b=cot66 cot78 can be written as tan24 tan12 bec cot(90-t)=tant;

tanA tanB = tanC tanD if A+B=C+D; or A+B =C-D or A-B=C+D or A-B=C-D;

as 42-6=24+12;

both are equal.

a/b=1

a=b