Question

if a tank was filled by two taps A and B can fill the tank in 20 hours and B can fill the tank in 30 hours and third type C can empty the tank in 1 hour then 10 me how much time will taken by A and B to fill the tank at once​

Answer 1

Answer:

Part of the tank filled when all the three pipes are opened for 10 hours

=10×(

15

1

+

20

1

−

25

1

)=10×(

300

20+15−12

)=

300

230

=

30

23

Remaining empty part = 1−

30

23

=

30

7

Part of the tank filled in 1 hour by pipes (A and B) =

15

1

+

20

1

=

60

4+3

=

60

7

∵

60

7

part is filled in 1 hour

30

7

part is filled in 2 hours

∴ Total time to fill the tank =10+2=12 hours