if a tap takes 15 min to fill,another tap takes 12 min to fill, and rhird tap can empty in 20 min in how much time tank will be filled?
Answers
Step-by-step explanation:
Part of the tank filled when all the three taps are opened simultaneously =(
15
1
+
12
1
−
20
1
)=
60
4+5−3
=
60
6
=
10
1
∴ The tank will be filled in 10 minutes.
Time required to get filled tank completely if all the taps are kept open together is 10 minutes.
Step-by-step explanation:
Given:
First tap can independently fill a tank in 15 minutes.
Second tap can independently fill a tank in 12 minutes.
Third tap can empty the tank completely in 20 minutes.
To Find: Time required to get filled tank completely if all the taps are kept open together,
Formula Used:
If a tap requires 'k' hours to fill up the tank, then part filled in 1 hr =1/k
If a tap requires 'n' hours to empty the full tank, then part emptied in 1 hr =1/n
Solution:
Quantity of water filled in tank by the first tap in one minute = 1/15
Quantity of water filled in tank by the second tap in one minute = 1/12
Quantity of water emptied from tank by the third tap in one minute =1/20
Quantity of water filled in tank in one minute, when all the 3 taps are opened = (1/15+1/12-1/20)
= (4+5-3)/60
=6/60 = 1/10
Time required to get filled tank =1/1/10 =10 minutes.
Thus, Time required to get filled tank completely if all the pipes are kept open together is 10 minutes.