Math, asked by vinaygoud0074, 6 months ago

if a tap takes 15 min to fill,another tap takes 12 min to fill, and rhird tap can empty in 20 min in how much time tank will be filled?

Answers

Answered by jasbirsingh56789
0

Step-by-step explanation:

Part of the tank filled when all the three taps are opened simultaneously =(

15

1

+

12

1

20

1

)=

60

4+5−3

=

60

6

=

10

1

∴ The tank will be filled in 10 minutes.

Answered by swethassynergy
0

Time required  to get filled  tank completely if all the  taps are kept open together is 10 minutes.

Step-by-step explanation:

Given:

First tap can independently fill a tank in 15 minutes.

Second tap   can independently fill a tank in 12 minutes.

Third tap  can empty the tank completely in 20  minutes.

To Find: Time required  to get filled  tank completely if all the  taps  are kept open together,

Formula Used:

If a  tap  requires 'k' hours to fill up the tank, then part filled in 1 hr =1/k

If a  tap  requires 'n' hours to empty the full tank, then part emptied in 1 hr =1/n

Solution:

Quantity of water filled in  tank by the  first   tap  in one minute = 1/15

Quantity of water filled  in  tank by the  second tap  in one minute = 1/12

Quantity of water emptied from tank  by the  third tap in one minute =1/20

Quantity of water filled in tank in  one minute, when all the 3  taps  are opened = (1/15+1/12-1/20)

                                                                                                                                = (4+5-3)/60

                                                                                                                                =6/60 = 1/10

Time required  to get filled  tank =1/1/10 =10 minutes.                                                        

                                                                                                       

Thus, Time required  to get filled  tank completely if all the pipes are kept open together is 10 minutes.

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