If a tells truth 4 times out of 5 and b tells truth 3 times out of 4. the probability that both expressing the same fact contradict each other is:
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Solution :-
Let A = The event that A speaks the truth
B = The event that B speaks the truth
Then,
P(A) = 4/5
P(B) = 3/4
Now,
A and B contradicts each other
= (A lies and B tells truth) or (A tells truth and B lies)
= P(A)*P(B - Lies) + P(A - Lies)*P(B)
= (4/5)*(1/4) + (1/5)*(3/4)
= 1/5 + 3/20
Taking L.C.M. of the denominators and then solving it.
= (4 + 3)/20
= 7/20
= (7*100)20
= 35 %
Answer.
Let A = The event that A speaks the truth
B = The event that B speaks the truth
Then,
P(A) = 4/5
P(B) = 3/4
Now,
A and B contradicts each other
= (A lies and B tells truth) or (A tells truth and B lies)
= P(A)*P(B - Lies) + P(A - Lies)*P(B)
= (4/5)*(1/4) + (1/5)*(3/4)
= 1/5 + 3/20
Taking L.C.M. of the denominators and then solving it.
= (4 + 3)/20
= 7/20
= (7*100)20
= 35 %
Answer.
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