Question

if a
$= 2 + \sqrt{3}$
than a
$- 1 \div a$
​

Answer 1

Answer:

this is so hard answer in which class you are reading

Step-by-step explanation:

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Answer 2

Answer:

2√3

Step-by-step explanation:

$a= 2+\sqrt{3}$

$so, \ \frac{1}{a}= \frac{1}{2+\sqrt{3}}$

$\rightarrow\frac{1}{a}= \frac{2-\sqrt{3}}{(2+\sqrt{3})(2-\sqrt{3})}$

$\rightarrow\frac{1}{a}= \frac{2-\sqrt{3}}{2^2-(\sqrt{3})^2}$

$\rightarrow\frac{1}{a}= \frac{2-\sqrt{3}}{4-3}$

$\rightarrow\frac{1}{a}= \frac{2-\sqrt{3}}{1}$

$\rightarrow\frac{1}{a}= 2-\sqrt{3}$

$Now , \ a - \frac{1}{a}= 2+\sqrt{3}-( 2-\sqrt{3})= 2+\sqrt{3}- 2+\sqrt{3} = 2\sqrt{3}$