Math, asked by Anonymous, 2 days ago

If A = \sf{\bigg [\:{\dfrac{1}{-2}}\:\:{\dfrac{5}{3}}\:\bigg ]\:and\:B\:=\:\bigg [\:{\dfrac{0}{4}}\:\:{\dfrac{-1}{-7}}\:\bigg ]}, Find 2A - 3B.​

Answers

Answered by Anonymous
3

Answer:

hope this answer helps

Attachments:
Answered by Anonymous
11

{\textsf{\textbf{\red{\underline{\underline{Given:}}}}}}

{ }

  • \sf{A\:=\:\bigg [\:{\dfrac{1}{-2}}\:\:\:{\dfrac{5}{3}}\:\bigg ]}

  • \sf{B\:=\:\bigg [\:{\dfrac{0}{4}}\:\:\:{\dfrac{-1}{-7}}\:\bigg ]}

{ }

{\textsf{\textbf{\red{\underline{\underline{Find:}}}}}}

{ }

  • \sf{Value\:of\:2A\:-\:3B}

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{\textsf{\textbf{\red{\underline{\underline{Solution:}}}}}}

{ }

\:\::\:\Longrightarrow\:\sf{2A\:-\:3B\:=\:2\bigg [\:{\dfrac{1}{-2}}\:\:\:{\dfrac{5}{3}}\:\bigg ]\:+\:(-3)\bigg [\:{\dfrac{0}{4}}\:\:\:{\dfrac{-1}{-7}}\:\bigg ]}

{ }

\:\::\:\Longrightarrow\:\sf{\bigg [\:{\dfrac{2}{-4}}\:\:\:\:{\dfrac{10}{6}}\:\bigg ]\:+\:\bigg [\:{\dfrac{0}{-12}}\:\:\:\:{\dfrac{3}{21}}\:\bigg ]}

{ }

\:\::\:\Longrightarrow\:\sf{\bigg [\:{\dfrac{2\:+\:0}{-4\:+\:(-12)}}\:\:\:{\dfrac{10\:+\:3}{6\:+\:21}}\:\bigg ]}

{ }

\:\::\:\Longrightarrow\:\sf{\bigg [\:{\dfrac{2}{-16}}\:\:\:{\dfrac{13}{27}}\:\bigg ]}

{ }

{ }

\:\therefore\:{\underline{\sf{Hence,\:the\:value\:is\:{\sf{\bf{\pink{\bigg [\:{\dfrac{2}{-16}}\:\:\:\pink{\dfrac{13}{27}}\:\bigg ]}}}}}}}.

{ }

\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━

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