Math, asked by prardhana31, 1 year ago

if a=
 \sqrt{3 }  -  \sqrt{2 }  \\  \div  \sqrt{3}  +  \sqrt{2}
and b=
 \sqrt{3}  +  \sqrt{2}  \\  \div  \sqrt{3}  -  \sqrt{2}
then,find the value of
 {a}^{2}  +  {b}^{2}  - 5ab

Answers

Answered by siddharth19402
1

 \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3}  +  \sqrt{2} }  \times  \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3} -  \sqrt{2}  }  = 5 - 2 \sqrt{6}  = a

similarly

b = 5 + 2 \sqrt{6}

so

 {a}^{2}  +  {b}^{2}  - 5ab =  {(a  - b)}^{2}  - 3ab

64+117=181


prardhana31: thank you very much
prardhana31: can you help me understand it better??
SK6731: This is wrong ans and totally wrong calculation
siddharth19402: don't go on calculation see the method
Answered by SK6731
2

Answer:

Step-by-step explanation:

In pic

.....

Hope it helps.

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