If A then adjoint of matrix A is
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Let A be of the order n×n
Since A adjA=∣A∣I
Therefore =∣A.adjA∣=∣A∣
n
=∣A∣∣adjA∣=∣A∣
n
⇒∣adjA∣=∣A∣
n−1
q
Since A is singular then ∣A∣=0
∣adjA∣=0 so adj A is also singular.
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