Question

if a thermometer read freezing point at 10 degree celsius and boiling point of water at 130 degrees celsius what is reading in thermometer actual temperature is 50 degree celsius

Answer 1

Answer:

Freezing point on thermometer =20 , Boiling point on thermometer =150 ,

Hence, number of equal parts on thermometer =150−20=130, temperature on celsius scale =20

o

C

Let temperature on thermometer =t ,

Therefore ,

130

t−20

=

100

60−0

,

⇒ t−20=78

⇒ t=78+20=98

o

Hope it helps

Answer 2

Actual temperature = 70°

Explanation:

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