If a thermometer reads freezing point if water as 20℃ and boiling point as 150℃
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Hey !
Seems like your question is incomplete.
Complete question :- If a thermometer reads freezing point if water as 20℃ and boiling point as 150℃, how much thermometer read when the actual temperature is 60℃ ?
Solution :- Here,
100 - 60 / 60 - 0 = 150 - x / x - 20
=> 40(x - 20) = 60 (150 - x)
=> x = 98°C
Good luck !
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