Question

If a torque of 60Nm acts on a disc tangentially for 3 sec find out its final angular velocity? Given that the moment of inertia of the disc is 12Kg m².



PLEASE ANSWER THE QUESTION AS SOON AS POSSIBLE ​

Answer 1

Answer:

we know

Torque= I * angular acceleration

60=12*α

α=5rad/s²

time taken = 3secs

initial ω'=0

we use ωfinal= αt

=5*3= 15 rad/s

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