Question

If a total of 6.67 x 10^-18J energy is received from the radiation of 6000Angstrom, then the number of photons received is

Answer 1

Answer:

Explanation:

Given wavelength =3000A∘

E=hν

c=hν

v=λc​

E=h.λc​

=6.626 x 10−34 × 3000 × 10−93 × 108​

=6.626 x  10−9108​

=6.626 x 10−34 X 108 X 107

=6.626 x 10−34   X 1015

E= 6.626 x 10−34   X 1019Joules.

Answer 2

Explanation:

Answer in the figure

Hope this will help you