Question

If a tower 30 m high, casts a shadow 103–√ m long on the ground, then what is the angle of elevation of the sun?

Answer 1

Given ... AB=30cm

$bc \: is \: 10 \sqrt{3}$

To find

$theta$

tan theta =p/b

tan theta =

$30 \div 10 \sqrt{3}$

=

$3 \div \sqrt{3}$

$\sqrt{3} \times \sqrt{3} \div \sqrt{3}$

$\sqrt{3}$

tan theta =

$\sqrt{3}$

=60⁰

So theta=60⁰...

Okay we can be friends.....

Answer 2

Hi there!

Plz check the attachment for answer..

Hope it will help u!!