If a tower 30 m high casts a shadow 10root 3 long on the gorund then what i s the angle of elevation of the sun
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60 degree is the angle of elevation of the sun
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In triangle ABC :
Take height of tower as the perpendicularThen the shadow as the base
So the solution is:
tan∅ = 30/10√3
tan∅ = 3/√3
tan∅ = √3 × √3 / √3 [ 3 = √3 × √3 ]
tan∅ = √3
tan∅ = tan 60°
∅ = 60°
Take height of tower as the perpendicularThen the shadow as the base
So the solution is:
tan∅ = 30/10√3
tan∅ = 3/√3
tan∅ = √3 × √3 / √3 [ 3 = √3 × √3 ]
tan∅ = √3
tan∅ = tan 60°
∅ = 60°
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