If a tower 30m high casts a shadow 10_/3m long on ground then what is angle of elevation of the sun
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Answer:
Ф=60°
Step-by-step explanation:
In ΔABC B=90°
C=Ф
tanФ=opposite/adjacent
=AB/BC
=30/10√3
=√3=tan60°
tanФ=tan60°
⇒Ф=60°
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