⏩If a tower is 50m high, cast a shadow 10√3m long on the ground, then what is the Angle of Elevation of the sun.
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In triangle ABC :
Take height of tower as the perpendicular
Then the shadow as the base
So the solution is:
tan∅ = 30/10√3
tan∅ = 3/√3
tan∅ = √3 × √3 / √3 [ 3 = √3 × √3 ]
tan∅ = √3
tan∅ = tan 60°
∅ = 60°
Therefore the angle of elevation is 60degree
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Answer:
answer is 60degree
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