Question

If a train 110 m long passes a telegraph pole in 3 seconds, then the time taken by it to cross a railway platform 165 m long is

Answer 1

HEY.

HERE IS THE ANSWER.

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As time = distance/speed
Distance covered to cross the pole =110 m

so, 3 s = 110 m / speed

so, speed = 110/3 m/s

Now to cross the platform distance covered=110+165 m = 275 m

so, time = 275/ (110/3) = 275×3 /110 = 7.5 sec

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THANKS.

Answer 2

Answer:

According to the given problem statement;

Distance covered by train in 3 seconds = 110 meters

Then the speed of train can be calculated by the relation;

Speed = distance / time

Speed = 110 / 3 m/s = 36.67 m/s

So the train moves with a speed of 36.67 meters per second.

Train crosses a platform of length = 165 meters

Time taken to cross the platform = ?

Total length of train and platform= 165 + 110 meters = 275 meters

Repeating the relation for velocity;

velocity = distance / time

Time = distance / velocity = 275 / 36.67

Time = 7.5 seconds

When a train 110 m long passes a telegraph pole in 3 seconds, then the time taken by it to cross a railway platform 165 m long is 7.5 seconds.